(((3-2j)^2)-4j)/2

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Solution for (((3-2j)^2)-4j)/2 equation: 


j in (-oo:+oo)

((3-(2*j))^2-(4*j))/2 = 0

((3-2*j)^2-4*j)/2 = 0

(3-2*j)^2-4*j = 0

(3-2*j)^2-4*j = 0

4*j^2-16*j+9 = 0

4*j^2-16*j+9 = 0

4*j^2-16*j+9 = 0

DELTA = (-16)^2-(4*4*9)

DELTA = 112

DELTA > 0

j = (112^(1/2)+16)/(2*4) or j = (16-112^(1/2))/(2*4)

j = (4*7^(1/2)+16)/8 or j = (16-4*7^(1/2))/8

(j-((16-4*7^(1/2))/8))*(j-((4*7^(1/2)+16)/8)) = 0

(j-((16-4*7^(1/2))/8))*(j-((4*7^(1/2)+16)/8)) = 0

((j-((16-4*7^(1/2))/8))*(j-((4*7^(1/2)+16)/8)))/2 = 0

( j-((16-4*7^(1/2))/8) )

j-((16-4*7^(1/2))/8) = 0 // + (16-4*7^(1/2))/8

j = (16-4*7^(1/2))/8

( j-((4*7^(1/2)+16)/8) )

j-((4*7^(1/2)+16)/8) = 0 // + (4*7^(1/2)+16)/8

j = (4*7^(1/2)+16)/8

j in { (16-4*7^(1/2))/8, (4*7^(1/2)+16)/8 }

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